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3 votes
Which table of values is correct for the equation y = 5(2)x

x y
0 5
1 10
2 40

x y
0 0
1 52
2 54

x
0 0
1 10
2 20

x y
0 5
1 10
2 20

1 Answer

4 votes

Answer:

Option D is correct.

x y

0 5

1 10

2 20

Explanation:

Given the equation:
y = 5(2)^x .....[1]

Here, x is the input variable and y is the output variable.

For x =0

Substitute in equation [1]; we have;


y = 5(2)^(0) = 5 \cdot 1= 5

For x = 1

Substitute in equation [1]; we have;


y = 5(2)^(1) = 5 \cdot 2= 10

For x =2

Substitute in equation [1]; we have;


y = 5(2)^(2) = 5 \cdot 4= 20

Therefore, the table values which is correct for the equation
y = 5(2)^x is;

x y

0 5

1 10

2 20

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