Answer:
13.994
![cm (5.sf)](https://img.qammunity.org/2023/formulas/mathematics/high-school/mse6nte2936x6ug3eopcng4c22twzt1sko.png)
Explanation:
We know that the base of the cylinder is a circular base.
So circumference of base =
![2\pi r](https://img.qammunity.org/2023/formulas/mathematics/high-school/lq9ocvc815y81kqkk2foo7l5ja0ltnznvd.png)
Given
![2\pi r=22cm\\\\r=(22)/(2\pi ) \\r=(11)/(\pi ) cm\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/x36197yb5ln0gczmj1ph6na7rhsbnf0u7u.png)
Volume of a cylinder =
= 539
![cm^(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/a93z5pb9ikie4exzf17c87u9jcyt6bqavt.png)
Substitute r into the formula for volume of cylinder.
Now, we will cancel
from the numerator and denominator.
![((121)/(\pi ) )h=539\\h = (539)/((121)/(\pi ) ) \\h = 539 * (\pi )/(121) \\h = 13.994cm(5s.f)](https://img.qammunity.org/2023/formulas/mathematics/high-school/m1zuwentve3sfc9khi9w12i93apt9nr9tj.png)