Answer:
The maximum safe rescue height is 104.6 feet above the height of the ground.
Explanation:
Consider a triangle ABC where C is the point where the rescue ladder is standing and AB be the building and Ladder making an angle of 72° as shown.
We have to find the height of the building.
Let x be the height of building
Using Trigonometric ratio,
![\sin C=\frac{\text{Perpendicular}}{\text{Hypotenuse}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bmd8pfwpsojadvd71vmq5uiqkj9xixd6e2.png)
![\sin 72^(\circ)=(AB)/(BC)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/coo0vg7diah6gen6iu7eua6trxngvv381i.png)
![\sin 72^(\circ)=(x)/(110)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5fathjuarstemej9942dxishg0hgdalhkx.png)
![x=110 * \sin 72^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rqo71qkeutvxdbdg3uik3ap8p0k6r20b8h.png)
![x=104.6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hjl2mim8cp9yoh8w61c5m1thwds4fipl73.png)
So, the maximum safe rescue height is 104.6 feet above the height of
the ground.