Question

Birdman is flying horizontally at a

speed of 28 m/s and a height of 87
m. Birdman releases a turd directly
above the start of the field. How far
from the start of the field should the
robot hold the bucket to catch the
turd?

Answer 1

117.88m

Step-by-step explanation:

We can use the formula [ s = ut + 1/2at^2 ] to solve this problem.

We know that constant acceleration is a = 9/8m/a^2, the initial velocity is 0, and the height is 87 so the only variable we need to solve for is "t".

87 = 0t + 1/2(9.8)(t^2)

t = √174/9.8

t = 4.21s

Now multiply the time by the speed given.

28m/s * 4.21s = 117.88m

Best of Luck!