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What is the remainder when (x^3-6x^2-42x+79) is divided by (x+5)?
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What is the remainder when (x^3-6x^2-42x+79) is divided by (x+5)?

User AlyssaAlex
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1 Answer

5 votes

Answer: The remainder is 14.

x^2-11x+13 R 14 is the full answer. I hope this helps!

Explanation:


User Krasu
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