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I need helping finding KMC.

I need helping finding KMC.-example-1

1 Answer

4 votes

Hello from MrBillDoesMath!

Answer:

See discussion below. (I think the desired answer is 130)


Discussion:

The problem needs to be clarified to give you a answer. Her'es why:

Argument 1:

When two lines intersect vertical angles are equal. So angle HMC =

angle RMK. That's equivalent to


5M + 15 = 7M +1 => subtract 5M from both sides

5M - 5M + 15 = 7M -5M +1 => subtract 1 from both sides

0 + 15 -1 = 2M + 1 -1 =>

14 = 2M =>

M = 7


As a straight line has 180 degrees

angle RMK + angle KMC = 180 => as angle RMK = 7M + 1

(7M + 1 ) + angle KMC = 180 => as M =7 from above

50 + angle KMC = 180 =>

angle KMC = 180 - 50 = 130.

I think this is the answer they want BUT notice


Argument 2.

Per the diagram, M can be interpreted as either the point of

intersection of the 2 lines or as the angle at the intersection of the two

lines. If the point of intersection were called, say Q, and M reserved

for angles, the problem would be clearer. BUt as I said above I think

they are looking for the answer found in Argument 1 (130 degrees)



Thank you,

MrB

User Eric V
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