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You and your mom enter a drawing with 3 different prizes. A total of 10 people entered the drawing, and prizes are awarded randomly.There are 336 ways to award the prizes.What is the probability that you win first prize and your mom wins second prize?

2 Answers

2 votes

Answer: 8

Step-by-step explanation: APEX

User Alaaeddine HFIDHI
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5 votes

Answer:


\textbf{Hence, The required Probability = }\bf(11)/(9380)

Explanation:

Total number of ways to award the prizes = 336

Total number of people entered in the quiz = 10 + 2 = 12


\text{Probability that the i win the first prize = }(12)/(336)

Now one prize has been awarded to me, so remaining number of ways to award the prizes = 336 - 1

= 335

Also, one person that is i has received the prize so persons left who can receive the prize = 12 - 1 = 11


\text{Probability that the my mom wins the second prize = }(11)/(335)

To find the required probability, Multiply both the above probabilities.


\textbf{Hence, The required Probability = }(12)/(336)* (11)/(335)=\bf(132)/(112560)=(11)/(9380)

User Kalkin
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