38.8k views
0 votes
A wheelchair ramp needs to be pitched at 8 degrees. If the ramp is to access an 18-inch step to a door what will be the length of the ramp to the nearest inch?

Please help

A wheelchair ramp needs to be pitched at 8 degrees. If the ramp is to access an 18-inch-example-1

1 Answer

3 votes

Answer : The length of the ramp to the nearest inch will be, 129.49

Step by step explanation :

As we know that,


\sin \theta =(Perpendicular)/(Hypotaneous)

In the given image, the value of
\theta(the angle between the base and the hypotaneous) is
8^o and the value of perpendicular is 18 inch.

Now we have to calculate the value of the hypotaneous by using above expression, we get


\sin \theta =(Perpendicular)/(Hypotaneous)


\sin 8^o=(18inch)/(Hypotaneous)


0.139=(18inch)/(Hypotaneous)


Hypotaneous=(18inch)/(0.139)


Hypotaneous=129.49inch

The hypotaneous is equal to the length of the ramp = 129.49 inch

Therefore, the length of the ramp to the nearest inch will be, 129.49

A wheelchair ramp needs to be pitched at 8 degrees. If the ramp is to access an 18-inch-example-1
User Tam Nguyen
by
4.3k points