Question

Point A(2, 2) and point D(−4, −3) are located on the grid. Which measurement is closest to the distance between point A and point D in units? A) 7.5 units B) 7.8 units C) 8.1 units D) 8.4 units

Answer 1

B) 7.8 units

Explanation:

To find the distance between 2 points

d = sqrt ( (x2-x1)^2 + (y2-y1)^2)

=sqrt( -4-2)^2 + (-3-2)^2)

= sqrt((-6)^2+(-5)^2)

= sqrt(36+26)

= sqrt(61)

=7.810249676

Answer 2

B

Explanation:

The distance formula is
`D=\sqrt{(y_2-y_1)^(2)+(x_2-x_1)^(2)}`

Where
`(x_1,y_1)` is the first coordinate (our case, point A(2,2)) &
`(x_2,y_2)` is the second coordinate (our case, point D(-4,-3))

Plugging these in into the formula gives us:

`D=\sqrt{(y_2-y_1)^(2)+(x_2-x_1)^(2)} \\D=\sqrt{(-3-2)^(2)+(-4-2))^(2)} \\D=\sqrt{(-5)^(2)+(-6)^(2)}\\ D=√(25+36) \\D=√(61) \\D=7.81`

Answer choice B is closest.