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Scenario 1: Make a cross between the following flies: 1. A heterozygous gray-bodied fly. 2. A homozygous black-bodied fly. What are the genotypes of Parent 1. Parent 2, and the offspring?

Parent 1: Gg; Parent 2: gg; Offspring: Gg, Gg, gg, gg



Parent 1: GG; Parent 2: gg; Offspring: GG, Gg, Gg, gg



Parent 1: gg; Parent 2: gg; Offspring: GG, GG, Gg, gg

Scenario 2: Make a cross between the following flies: 1: A heterozygous gray-bodied fly and 2: A heterozygous gray-bodied fly. What is the dominant phenotype in this question?

gray-bodies



black-bodies

Scenario 3: Make a cross between the following flies: 1. A homozygous long-winged fly and 2. A homozygous vestigial-winged fly. What are the genotypes of the parents and the offspring?

Parent 1: Ll; Parent 2: LL; Offspring LL, Ll, ll, ll



Parent 1: LL; Parent 2: ll; Offspring: Ll, Ll, Ll, Ll



Parent 1: ll; Parent 2: ll; Offspring: Ll, Ll, ll, ll

Scenario 4: Make a cross between the following flies: 1. A homozygous long-winged fly and 2. A heterozygous long-winged fly. What will the offspring look like?

100% long-winged flies



50% long-winged flies & 50% vestigial-winged flies



75% long-winged flies & 25% vestigial-winged flies



100% vestigial-winged flies

Scenario 5: Make a cross between 1. A heterozygous long-winged fly and 2. A heterozygous long-winged fly.What is the ratio of long-winged offspring to short-winged offspring?


1:1



all will have long wings



3:1

Scenario 6: Make a cross between two flies that are expected to produce 50% homozygous gray-bodied offspring and 50% heterozygous gray-bodied offspring. What will the genotype of the parents be?

Both parents will be Gg.



One parent will be GG and the other will be gg.



Both parents will be gg.



One parent will be Gg and the other will be GG.

Scenario 7: Make a cross between two flies that are expected to produce 50% heterozygous long-winged offspring and 50% vestigial-winged offspring. What will the genotypes and phenotypes of the parents be?

Ll, long-winged; ll, vestigial-winged



ll, short-winged; ll, short-winged



LL, long-winged; ll, short-winged



Both Ll, long-winged

Scenario 8: Make a cross between flies that are expected to produce all heterozygous, gray-bodied offspring. What will the phenotypes of the parents be?

3 points



Both parents will have gray bodies.



One parent will have a gray body and one parent will have a black body.



Both parents will have black bodies.

Scenario 9: Make a cross between two flies that are expected to have vestigial-winged offspring. What will the phenotypes of the parents be?

3 points



Both parents will have long wings.



One parent will have long wings and one parent will have short wings.



Both parents will have short (vestigial) wings.

Scenario 10: Make a cross between two parents that are expected to have all black-bodied offspring. What will the genotype of the parents be?

3 points



Parent 1: GG, Parent 2: gg



Parent 1: Gg, Parent 2: Gg



Parent 1: gg, Parent 2: gg

User Gib
by
7.6k points

2 Answers

5 votes

Answer:

Scenaro 1:

Answer:

Gg * gg

Gg , Gg , gg , gg

Parent 1 :Gg

Parent 2: gg

Scenario 2:

Answer:

Gg * Gg

GG , Gg , Gg , gg

GG,Gg,Gg = will be gray (75%).

gg = will black (25%).

Gray will be dominent.

Scenario 3:

Answer:

LL: Homozygous long winged fly

ll: Homozygos vestigial winged fly

LL * ll

Ll , Ll , Ll , Ll

All offsprings will be hetrozygous long winged

Scenario 4:

Answer:

Homozygous long winged fly : LL

Hetrozygous long winged fly : Ll

LL * Ll

LL , Ll , LL , Ll

100% long winged flies.


Scenario 5:

Answer:

Hetrozygous long winged fly :Ll

Ll * Ll

LL , Ll , LL ,ll

3 : 1

long winged : vestigial winged.

Scenario 6:

Answer:

GG * Gg

GG , Gg , GG ,Gg

GG 50% homozygous grey bodies.

Gg 50% hetrozygous grey bodies.


Scenario 7:

Answer:

Ll * ll

Ll , Ll , ll , ll

Ll :long winged .

ll : vestigial winged.

Scenario 8:

Answer:

GG * gg

Gg , Gg , Gg , Gg

One parent will have gray body GG.

Second parent will have black body gg.

Scenario 9:

Answer:

ll * ll

ll , ll , ll , ll

Both parents will have vestigial wings .

Scenario 10:

Answer:

gg * gg

gg , gg ,gg , gg

Both parents will have black bodies.


User Constance
by
8.3k points
5 votes

Scenario 1 :

The gray bodied fly is heterozygous, which means that the gray color is dominant (G), while the black color (g) of the body is recessive. Hence, the genotype of the parents and the offspring will be:

Parent 1: Gg

Parent 2: gg

Offspring: Gg, Gg, gg, gg


Scenario 2 :

The condition that appears is a heterozygous condition is dominant, and hence, the dominant phenotype in this question is 'gray bodies'.


Scenario 3 :

The homozygous long winged fly (L) and the homozygous vestigial winged fly (l) will have the following genotypes:

Parent 1: LL

Parent 2: ll

Offspring: Ll, Ll, Ll, Ll


Scenario 4:

The long-winged phenotype is dominant as it is visible in a heterozygous condition. Hence, a cross between a homozygous long-winged fly and a heterozygous long-winged fly will result in 100% long-winged flies.


Scenario 5:

The long-winged allele is dominant (L) over the vestigial/short -wing allele. Therefore, a cross between a heterozygous long-winged fly and an heterozygous long-winged fly will result in the following of long-winged offspring to the short-winged offspring : '3:1'


Scenario 6:

The gray body color allele (G) is dominant over the black body color allele (g). Hence, in order to produce offsprings out of which 50% are homozygous gray bodies, and 50% are heterozygous gray bodied, the allele of the parents must be:

Parent 1: GG

Parent 2: Gg


Scenario 7:

The long-winged allele is dominant (L) over the vestigial/short -wing allele (l). Hence in order to produce offspring out of which 50% are heterozygous long-winged and 50% are vestigial-winged, the genetotypes of the parents must be :

Parent 1: ll

Parent 2: Ll


Scenario 8:

The offsprings of a homozygous gray bodied fly (GG) and a homozygous black bodied fly (gg) will be heterozygous gray bodied flies (Gg). Hence, the phenotype of the parents is:

One will have gary body and other will have black body.


Scenario 9:

The long-winged allele is dominant (L) over the vestigial/short -wing allele (l). Hence in order to produce offspring that are all vestigial winged, the genotype of the parents should be ll and ll. Hence, the phenotype of the parents will be:

Both parents will have vestigial wings.


Scenario 10:

The gray body color allele (G) is dominant over the black body color allele (g). Hence, in order to produce offsprings that are black bodied, the genotype of the parents should be gg and gg. Hence, the phenotype of the parents will be:

Both will be black bodied.

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User Antonmos
by
8.5k points