Question

HELP ASAP!!!

REASONS ONLY

Given: ABCD is a parallelogram, FC is congruent to EC, DE bisects BC and BF bisects DC Prove: ABCD is a rhombus

(i put random reasons just to show all of them)

Answer 1

2) perpendicular lines form right angles

3) perpendicular lines form right angles

4) all right angles are congruent

5) reflexive property

6) ASA

7) CPCTC

8) ABCD is a rhombus because it is a parallelogram with a pair of consecutive congruent sides