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A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is found to be 40.28% B, 52.20% N, and 7.53% H. What is the empirical formula for this molecule? Enter in the empirical formula in the form BxNyHz

User Morganics
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Empirical formula is the simplest ratio of components making up a compound.

The percentage composition of each element has been given

therefore the mass present of each element in 100 g of compound is

B N H

mass 40.28 g 52.20 g 7.53 g

number of moles

40.28 g / 11 g/mol 52.20 g / 14 g/mol 7.53 g / 1 g/mol

= 3.662 mol = 3.729 mol = 7.53 mol

divide the number of moles by the least number of moles, that is 3.662

3.662 / 3.662 3.729 / 3.662 7.53 / 3.662

= 1.000 = 1.018 = 2.056

the ratio of the elements after rounding off to the nearest whole number is

B : N : H = 1 : 1 : 2

therefore empirical formula for the compound is B₁N₁H₂

that can be written as BNH₂

User Jesper Kristiansen
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