Question

randall wants to mix 32 lb of nuts worth $2 per lb with some nuts worth $6 per lb to make a mixture worth $5 per lb. how many pounds of $6 nuts must use

Answer 1

96 lb

Explanation:

We are given that

Number of nuts =32 lb

Cost of 1 nut=$2

We have to find that how many pounds of $6 nuts must used.

Let x pounds be the nuts worth $6 per lb must be used.

Mixture =32+x

Cost of one lb nut in mixture =$5

According to question

`32(2)+x(6)=(32+x)* 5`

`64+6x=160+5x`

`6x-5x=160-64`

`x=96`

Hence, 96 lb of nuts worth $6 per lb must used.

Answer 2

Answer: 96 pounds

Explanation:

Let x be the number of pounds of $6 nut required .

then you know the weight of the resulting mixture = (x+32)

The total cost of the mixture=
`5(x+32)`

According to the question,

`5(x+32)=32*2+6x\\\Rightarrow\ 5x+160=64+6x\\\Rightarrow\ 6x-5x=160-64\\\Rightarrow\ x=96`

Hence, Randall must use 96 pounds of $6 nuts.