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If A+B =45 then prove that i) CotA.CotB-CotA-CotB=1​

If A+B =45 then prove that i) CotA.CotB-CotA-CotB=1​
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If A+B =45 then prove that
i) CotA.CotB-CotA-CotB=1​

User DJJ
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1 Answer

2 votes

Answer:

Explanation:


if A+B=45\\tan(A+B)=tan(45)\\(tanA+tanB)/(1-tanA.tanB)=1\\ \implies tanA+tanB=1-tanA.tanB\\(1)/(cotA)+(1)/(cotB)=1-(1)/(cotA)(1)/(cotB), \{tanX=(1)/(cotX) \}\\ cotA+cotB=cotA.cotB-1\\cotA.cotB-cotA-cotB=1.

User Gfan
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