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factor 12t2 + 70t + 72 a= 12(t+3) (t+2) b= 2(3t+4)(2t+9) c= 2(3t+ 9) (2t+4) d= (6t+8)(2t+9)
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factor 12t2 + 70t + 72 a= 12(t+3) (t+2) b= 2(3t+4)(2t+9) c= 2(3t+ 9) (2t+4) d= (6t+8)(2t+9)

User Jake Berger
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1 Answer

6 votes

Answer:

b = 2(3t + 4)(2t + 9)

Explanation:


12t^2+70t+72=2(6t^2+35t+36)=2(6t^2+27t+8t+36)\\\\=2[3t(2t+9)+4(2t+9)]=2(2t+9)(3t+4)

User ArcherBird
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