Question

Finish the distance formula. | P1P2 | = d=

Answer 1

`\left|P_1P_2\right|=d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Explanation:

Let the coordinates of the given point are as follows,

`P_1=(x_1,y_1)\:\:and\:\:P_2=(x_2,y_2)`

Now The distance between point
`P_1\:\:andP_2` is given by,

`\left|P_1P_2\right|=√((x_2-x_1)^2+(y_2-y_1)^2)`

Therefore,
`\left|P_1P_2\right|=d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Answer 2

`P_1(x_1;\ y_1);\ P_2(x_2;\ y_2)\\\\|P_1P_2|=d=√((x_2-x_1)^2+(y_2-y_1)^2)}`