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A meter stick is balanced at the 50 cm mark. You tie 70 N weight at the 30 cm mark. What weight at the 90 cm mark would create a rotational equilibrium?
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A meter stick is balanced at the 50 cm mark. You tie 70 N weight at the 30 cm mark. What weight at the 90 cm mark would create a rotational equilibrium?

User Bigstylee
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1 Answer

1 vote
70x(50-30) = W x (90-50)
1400 = W x 40
W = 35N
User Timon De Groot
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5.3k points
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