Question

In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

A. H2O
B. Cl
C. H
D. OH
E. None Of The Above (This Is Not A Redox Reaction)

Answer 1

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In
`H_2O` , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in
`Cl^-` is -1. On product side, the oxidation number of hydrogen in
`H_2` is zero and in
`OH^-` the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in
`Cl_2` is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H