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1 vote
F(x) = g(x+1)

f(y) = 2018y + 2016y +. . . . .+ 2y

g(x) = h(2x)-x

If h(2018) =
a^(3) and a is an integer, then a = ?

User Arun Redhu
by
8.7k points

1 Answer

4 votes


g(x)=h(2x)-x\implies h(2x)=g(x)+x


f(x)=g(x+1)\implies g(x)=f(x-1)

Taken together, we get


h(2x)=f(x-1)+x

Since
2018=2\cdot1009, the above gives


a^3=f(1008)+1009

We have


f(y)=\displaystyle\sum_(i=0)^(1008)(2018-2i)y=1019090y

so that


a^3=1019090\cdot1008+1009


a^3=1027243729=1009^3


\implies a=1009

User Klauskpm
by
8.4k points

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