Answer:
38.33 m
Explanation:
We are given that Mary is flying a kite with a 50 - meter string.
The string is making a 50 degrees angle with the ground
We have to find the height above the ground of the kite
Let x be the height of kite above the ground
![\theta=50^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q2uax4wng1jsh5wyt4uql0ry2walhi56ib.png)
Height of string =Hypotenuse
In aright angled triangle ABC
![sin \theta=(Opposite side of angle )/(Hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gzjonnp03b5q5dko85neyfthy27kqj3r2x.png)
Substitute the values then we get
![sin 50^(\circ)=(x)/(50)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/15eavre4z0iu6abmjn3c8oipvt7lmh51kc.png)
![0.766=(x)/(50)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/otsi876hj9okgbogu1srcnm7x4m8e4ao37.png)
![x=50* 0.766](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9kz5ay7lhw9bhj4jy7he5gxzuer3huz5u9.png)
![x=38.33 m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tzn9scc9dqk5gsyho2ncijh3bsizw6ywlc.png)
Hence, the height of kite above the ground=38.33 m