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Mary is flying a kite with a 50-meter string. The string is making a 50 degree angle with the ground. How high above the ground is the kite

User Woohyung
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2 Answers

2 votes

Answer:

38.3 meters to the nearest tenth.

Explanation:

sin 50 = opposite / hypotenuse

= height of the kite / length of the string

sin 50 = h / 50

h = 50 sin 50

= 38.3 meters (answer).

User Insanity
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4.7k points
3 votes

Answer:

38.33 m

Explanation:

We are given that Mary is flying a kite with a 50 - meter string.

The string is making a 50 degrees angle with the ground

We have to find the height above the ground of the kite

Let x be the height of kite above the ground


\theta=50^(\circ)

Height of string =Hypotenuse

In aright angled triangle ABC


sin \theta=(Opposite side of angle )/(Hypotenuse)

Substitute the values then we get


sin 50^(\circ)=(x)/(50)


0.766=(x)/(50)


x=50* 0.766


x=38.33 m

Hence, the height of kite above the ground=38.33 m

Mary is flying a kite with a 50-meter string. The string is making a 50 degree angle-example-1
User Mayur Borad
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