Answer: The kinetic energy of an apple at 100 m of height while falling is 49 J.
Step-by-step explanation:
Mass of the apple = 0.100 kg
Height at that instant when apple was at verge of falling = 150 m
The sum of the potential energy and kinetic remains constant.
Sum of P.E and K.E energy at height if 150 m

Kinetic energy is zero at initial position

Sum of P.E and K.E at height if 100 m

Kinetic energy is not zero during falling of an apple

K.E = 147 J - 98 J= 49 J
The kinetic energy of an apple at 100 m of height while falling is 49 J.