Question

Determine the mass of 1 mol of gold (Au), of aluminum chloride (AlCl3), and of glucose (C6H12O6)

Answer 1

Answer: Mass of 1 mol of gold (Au) is 197g , of aluminum chloride
`(AlCl_3)` is 133.5 g and of glucose
`(C_6H_(12)O_6)` is 180 g

Step-by-step explanation: Mass of 1 mole of a substance is called its molar mass.

a) 1 mole of
`Au` contains
`6.023* 10^(23)atoms` and weigh 197g.

b) 1 mole of
`AlCl_3` will weigh=
`1* {\text {mass of 1 mole of Aluminium}}+3* {\text {mass of 1 mole of chlorine atom}}`

Thus mass of 1 mole of
`AlCl_3` will be
`=1moles* {27g/mol}+3moles* {35.5g/mol}=133.5g`

c) 1 mole of
`C_6H_(12)O_6` will weigh=
`6* {\text {mass of 1 mole of carbon}}+12* {\text {mass of 1 mole of hydrogen atom}}+6* {\text {mass of 1 mole of oxygen}}`

1 mole of
`C_6H_(12)O_6` will weigh=
`6* 12g/mol+12* 1g/mol+6* 16g/mol=180g`