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Which value must be added to the expression x^2+x to make it a perfect-square trinomial? A.1/4 B.1/2 C.1 D.4

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Hello from MrBillDoesMath!

Answer:

Choice A, 1/4


Discussion:

Consider the perfect square

(x + a)^2 = x^2 + (2a)x + a^2

The constant term (a^2) equals 1/2 the coefficient of x (i.e. 2a), squared.

Let's apply this idea to x^2 + x

x^2 + x = => as 2 * 1/2 = 1

x^2 + ( 2 * 1/2)x =

( x^2 + (2* 1/2)x + ( 1/2) ^2 ) - (1/2) ^2 =

as constant term to add is 1/2 coefficient of x (that is, 1/2) and

(1/2)^2 - (1/2)^2 = 0

(x + 1/2) ^ 2 - (1/2)^2

In other words add the constant (1/2)^2 = 1/4, which is Choice A.


Thank you,

MrB

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