Question

The rectangle shown has a perimeter of 80 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

Answer: Dimensions of rectangle are 12 cm and 28 cm .

Explanation:

Since we have given that

Perimeter of rectangle = 80 cm

Let the length of rectangle be x

Let the width of rectangle would given by

`2x+4`

According to question,

`\text{Perimeter of rectangle}=2(L+B)\\\\80=2(x+2x+4)\\\\(80)/(2)=3x+4\\\\40=3x+4\\\\40-4=3x\\\\36=3x\\\\x=(36)/(3)\\\\x=12\ cm`

Hence, Length of rectangle is 12 cm

Width of rectangle be

`2x+4=2* 12+4\\\\24+4=28\ cm`

Therefore, Dimensions of rectangle are 12 cm and 28 cm .