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Please show the work as well for #2

Please show the work as well for #2-example-1
User Ed Willink
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1 Answer

4 votes

Answers:

(a) 508 THz; (b) 337 zJ

Step-by-step explanation:

The formula relating the frequency (f) and wavelength (λ) of a photon is

fλ = c Divide both sides by λ

f = c/λ

The formula for the energy of a photon is

E = hf

Data:

c = 2.998 × 10⁸ m·s⁻¹

λ = 590 nm

h = 6.626 × 10³⁴ J·s

Calculations:

(a) Frequency

f = 2.998 × 10⁸/(590 × 10⁻⁹)

= 5.08 × 10¹⁴ s⁻¹

= 508 × 10¹² s⁻¹

= 508 THz

(b) Energy

E = 6.626 × 10⁻³⁴ × 508 × 10¹²

= 3.37 × 10⁻¹⁹ J

= 337 × 10⁻²¹ J

= 337 zJ

User Andriy Kryvtsun
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