Answer:
BE = 3 in; EF = 2 in; FC = 3 in
Explanation:
∠EAD ≅ ∠AEB ≅ ∠EAB so ΔABE is isosceles and AB ≅ BE = 3 in.
Likewise, ∠FDC ≅ ∠FDA ≅ ∠DFC, so ΔDCF is isosceles and AB ≅ BC ≅ FC = 3 in.
Then EF = 8 in - 3in - 3 in = 2 in
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