Answer:
Dimensions of box
Length is 12 feet
Width is 3 feet
Explanation:
Let's assume length of sandbox is L
width of box is W
we are given
A rectangular sandbox has a width that's 1⁄4 of its length
so, we can write as
![W=(1)/(4)L](https://img.qammunity.org/2020/formulas/mathematics/college/nhxcjeet1dunx1kh9j9q3vx77jvstg5b69.png)
we know that
area = length*width
so, we get
![A=L* W](https://img.qammunity.org/2020/formulas/mathematics/high-school/ejgkkc14n7tkdr0kyi2shsxf45a2tozcla.png)
now, we can plug back W
![A=L* (1)/(4)L](https://img.qammunity.org/2020/formulas/mathematics/college/3mz54v3yyj80n6kr7cxpoj356928anjvm8.png)
we can set Area=36
![36=L* (1)/(4)L](https://img.qammunity.org/2020/formulas/mathematics/college/v54wmmr69hhrlz9rwd3d3fjn9cp4rmzbcp.png)
now, we can solve for L
![L^2=144](https://img.qammunity.org/2020/formulas/mathematics/college/j8yjlhb9jfmtn7ziayl1a7sr61f5j88cnz.png)
![L=12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qpjq4g633spxq3iqicfhlhqpokiei5x33q.png)
now, we can find W
![W=(1)/(4)* 12](https://img.qammunity.org/2020/formulas/mathematics/college/442y3edodvlbemdst3bobxzy6x5clkuz8z.png)
![W=3](https://img.qammunity.org/2020/formulas/mathematics/college/ix5iuh7l4gf7u52f3wgveja4kixj4r2tqe.png)
So, dimensions of box
Length is 12 feet
Width is 3 feet