Question

Calculating the acceleration of two people pulling a box with same force and angle.

Answer 1

Here as we can see there we be net horizontal force acting on it

`F_x = F_1cos20 + F_2cos20`

also we know that

`F_1 = F_2 = 80 N`

now we will have

`F_x = 2(80cos20)`

`F_x = 150.35 N`

now for net force of box we know

`F_x - F_f = ma`

`150.35 - 100 = ma`

`20a = 50.35`

`a = 2.52 m/s^2`

so acceleration of the box will be 2.52 m/s/s