How much does 2.3 moles of Mg(NO2)2 weigh?

asked Jul 17, 2023 54.7k views

8 votes

by Scobi

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4 votes

Answer:

mass = 266.8 g

Step-by-step explanation:

mass = no. of moles x molar mass (
M_r )

$M_r \space\ \space\ of$
Mg(NO_2)_2 = 24 + 2[14 + 2(16)]

= 116

∴ mass = 2.3 x 116

= 266.8 g

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