Question

Given:

2LiBr + Ba → BaBr2 + 2Li

In this chemical reaction, 325 grams of barium (Ba) react completely. How many moles of lithium (Li) are produced?

Answer 1

4.73 mol for Edmentum users

Answer 2

Answer: 4.74 moles

Explanation:

`2LiBr+Ba\rightarrow BaBr_2+2Li`

Moles of Ba=
`\frac{\text {given mass}}{\text {molar mass}}`

Moles of Ba=
`(325g)/(137g/mol)=2.37 moles`

According to given balanced equation,

1 mole of Barium gives 2 moles of Li

Thus 2.37 moles of Barium gives=
`(2)/(1)* 2.37=4.74 moles`

Thus 4.74 moles of lithium will be produced by 135 g of barium.