Question

A 5.0 kg ball is whirled on a 1.2 m string so that the ball moves in uniform circular motion in a horizontal plane. The centripetal force is 22 N. What is the tangential speed of the ball?

Answer:
2.3 m/s
Fc=22N
m= 5.0kg
r= 1.2m
vt= √(Fc* r /m)
√(22N *1.2 / 5.0kg) = 2.3 m/s

Answer 1

Answer: The tangential speed of the ball is 2.3 m/s.

Step-by-step explanation:

Mass of the ball ,M= 5.0 kg

Length of the string to which the ball is tied = r = 1.2 m

Tangential speed of the ball - v

Centripetal force acting = 22 N

`F_(c)=(M* (^2))/(r)`

`22 N=(5.0 kg* v^2)/(1.2 m)`

`v^2=(22N* 1.2 m)/(5.0 kg)=5.28 m^2/s^2`

`v=√(5.28 m^2/s^2)=2.297 m/s\approx 2.3 m/s`

The tangential speed of the ball is 2.3 m/s.