Question

There are three consecutive even integers. If twice the first integer added to the second is 268, 244 find all three integers.

Answer 1

The numbers would be 89,414 , 89,416, and 89,418

Explanation:

In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.

2(x) + x + 2 = 268,244

3x + 2 = 268,244

3x = 268,242

x = 89,414

Since the first number is 89,414, we know the next two are 89,416 and 89,418.