Question

6) A basket contains 5 yellow, 3 blue and 2 white balls. If a ball is drawn randomly from the basket, find the probability of not getting a blue ball.​

Answer 1

`|\Omega|=5+3+2=10\\|A|=5+2=7\\\\P(A)=(7)/(10)=70\%`

Answer 2

Answer: 70%

Explanation:

A basket contains:

5 yellow balls

3 blue balls

2 white balls

What would be the probability of randomly picking a ball and the ball not being blue?

So, we can find the probability of picking up a blue ball. Let's do that first.

To calculate the probability of getting a blue ball, we need to divide the number of blue balls by the number of possible balls.

The number of blue balls = 3

The total number of balls = 2 + 3 + 5 = 10 balls

3 blue balls divided by 10 balls = 0.3.

If you multiply 0.3 by 100%, it will give you a probability of finding a blue ball equal to 30%

Now, we just need to find the probability of NOT finding a blue ball. Because we have 30% of finding a blue ball, we just need to subtract 30% from 100%.

100 - 30$ = 70%

The probability of not getting a blue ball is equal to 70%.

Hope I Helped!