Question

Bill and Mary wanted to have a snack after school. They heated some milk in a pot on the stove to make hot chocolate. They also popped some popcorn in the microwave oven. How did Bill and Mary transfer heat energy to make these snacks?

Question 10 options:


Heating milk by conduction as the pot is on the stove; popping popcorn by radiation in the microwave


Heating milk by convection as the pot is on the stove; popping popcorn by conduction in the microwave


Heating milk by radiation as the pot is on the stove; popping popcorn by radiation in the microwave


Heating milk by radiation as the pot is on the stove; popping popcorn by convection in the microwave

Answer 1

The correct answer is A. Heating milk by conduction as the pot is on the stove; popping popcorn by radiation in the microwave

Step-by-step explanation:

Conduction and radiation are two different methods to transfer thermal energy (heat). In the case of conduction, this occurs due to direct contact between objects with different thermal energy. This implies the process of heating milk occurs due to conduction because the pot and the milk are in direct contact with the stove which is hot, and this transfers heat to the pot and milk.

On the other hand, radiation occurs as heat is transferred through waves or particles. This applies to the popcorn in the microwave oven because microwaves emit electromagnetic waves to heat food. Thus, in the case presented heating milk occurs by conduction and popping popcorn occurs by radiation.

Answer 2

Heating milk by conduction as the pot is on the stove; popping popcorn by radiation in the microwave.

Step-by-step explanation:

• Heat is transfer from the stove to the pot containing milk by conduction between the surface of stove to that of the pot.

• Heat transfer in the microwave oven by radiation through short, high-frequency waves.

• So, The right choice is Heating milk by conduction as the pot is on the stove; popping popcorn by radiation in the microwave.