Question

Please I need help with this 2 calc questionssss. Thank you

Answer 1

Question 14

As we approaching from the negative side,
`|x-3|=3-x`.

So, we have
`\lim_(x \to 3^(-))=(3-x)/(x-3)=(-(x-3))/(x-3)=\boxed{-1}`

and thus the limit exists at x=3.

Question 15

For the top part of the function,
`(9-9)^(2)=0`

For the bottom part of the function,
`9-9=0`

As both one-sided limits are equal, L = 0, and thus the limit exists at x=9.