Question

The reactant side of a balanced chemical equation is shown below.

Al2(SO4)3 + 3Cl2 →

How many chlorine atoms are there on the product side in the equation?

2
5
6
7

Answer 1

Matter can be neither created or destroyed so if we 3mol of Cl2 then we have 6 total

So the answer is 6

Answer 2

Answer: Option (c) is the correct answer.

Step-by-step explanation:

A reaction equation in which there are equal number of reactant and product molecules is known as a balanced equation.

For example,
`Al_(2)(SO_(4))_(3) + 3Cl_(2) \rightarrow AlCl_(3) + SO_(4)`

Number of atoms on reactant side are as follows.

Al = 2

`SO_(4)` = 3

Cl = 6

Number of atoms on product side are as follows.

Al = 1

`SO_(4)` = 1

Cl = 3

Therefore, to balance this equation multiply
`AlCl_(3)` by 2 and
`SO_(4)` by 3 on product side.

Hence, the balanced chemical equation is as follows.

`Al_(2)(SO_(4))_(3) + 3Cl_(2) \rightarrow 2AlCl_(3) + 3SO_(4)`

Thus, we can conclude that number of total chlorine atoms on product side are 6.