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what is the iterative rule for each sequence? (show work) 200,250,300,350,400,450 200,220,242,266,292,322

User Silom
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1 Answer

6 votes

Answer:


a_n=150+50n


a_n=n^2+17n+182

Explanation:

We have been given two sequence:

200,250,300,350,400,450

200,220,242,266,292,320

In first sequence We can see that there is common difference of 50 between consecutive terms:

So, we can use the formula of arithmetic sequance which is:


a_n=a+(n-1)d

Where, a is first term and d is common difference n is the number of terms:


a_n=200+(n-1)50


a_n=150+50n

Now, for second sequence:

200,220,242,266,292


a_n=n^2+17n+182 is the iterative rule

If we put n=1 in above formula we will get
a_n=200

At n=2,
a_n=220

And so on... by substituting consecutive values as in sequence given.



User Evk
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