Answer: AAS
Explanation:
Given: In ΔABC and ΔDEF
∠B≅∠E [right angle]
∠A≅∠D
![\overline{BC}\cong\overline{EF}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/736omp8nccy06nejrwmp4wpcxlv8tj7g4w.png)
As there is two angles and one non included side of ΔABC is congruent the two corresponding angles and one non- included side of ΔDEF, therefore, by AAS congruence rule.
ΔABC ≅ΔDEF
AAS congruence postulate :- Triangles are congruent if two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.