Answer: Average velocity of CO₂ = 0.059 m/s.
Step-by-step explanation:
- Average velocity of a molecule = √(3KbT / molar mass)
- Kb: Boltzmann constant and T: the temperature (K)
- At constant temperature; the average velocity of a molecule is inversely proportional to square root of its molar mass (velocity ∝ 1 / √molar mass).
For two molecules (CH₄ & CO₂):
- Velocity of CH₄ / Velocity of CO₂ = √(molar mass CO₂ / molar mass CH₄)
- molar mass of CH₄ = 16.0 g/mol & molar mass of CO₂ = 44.0 g/mol and the average velocity of CH₄ = 0.098 m/s.
- (0.098 / average velocity of CO₂) = √(44.0 / 16.0)
- Average velocity of CO₂ = 0.098 / √(44.0 / 16.0) = 0.059 m/s.