131k views
1 vote
Lemons tastes sour to some people. This sourness is inherited through the TAS2R38 gene. About 65% of the population has this gene. You want to estimate the proportion of Americans who have this gene. How large a sample must you test, with a 2% margin of error and 99% confidence, to estimate the proportion of people who carry the TAS2R388 gene?

User Felguerez
by
5.0k points

2 Answers

4 votes

Answer:

3775

Explanation:

I took the test

User Anderson Fortaleza
by
5.5k points
0 votes

Answer:

We are given:


\hat{p}=0.65

Margin of error
E=0.02

Confidence level = 0.99

We need to find the sample size to estimate the proportion of people who carry the TAS2R388 gene.

The formula for finding the sample size is:


n=\hat{p} (1-\hat{p})\left (\frac{z_{(0.01)/(2)}}{E} \right )^(2)

Where:


z_{(0.01)/(2)}=2.576 is the critical value at 0.01 significance level.

Therefore, the required sample size is:


n=0.65(1-0.65) \left((2.576)/(0.02) \right)^(2)


=0.2275 * 16589.44


=3774.1 \approx 3774

Therefore, the required sample size is 3774


User Eustatos
by
5.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.