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3 votes
In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (-3, -2) and (5, 5)?

1 Answer

5 votes

Answer:

10.630

Explanation:


\sqrt(x_(2)  -x_(1))^(2) + (y_(2) -y_(1))^(2)


\sqrt( 5-(-3)^(2) + (5- (-2)^(2)

(5 - ( - 3)^2 = 64

(5 - ( -2)^2 = 49

49 + 64

113


\sqrt113

10.630


I hope this helps

User XMight
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