Question

A coin is flipped and a random marble is picked from a bag of 10 marbles. Two of the marbles in the bag are red. What is the probability of the coin landing on tail and a red marble being drawn?

Answer 1

`(1)/(10)` is the probability of the coin landing on tail and a red marble being drawn.

Explanation:

Given A coin is flipped and a random marble is picked from a bag of 10 marbles. Two of the marbles in the bag are red. we have to find the probability of the coin landing on tail and a red marble being drawn.

P(a red marble)=
`(No.\thinspaceof\thinspace red\thinspace marbles)/(Total\thinspace marbles)`

=
`(2)/(10)`

P(getting a tail)=
`(1)/(2)`

Since both events are independent.

∴ P(he coin landing on tail and a red marble being drawn)

=
`P(getting\thinspace a\thinspace tail)* P(a\thinspace red\thinspace marble\thinspace drawn)`

=
`(2)/(10)* (1)/(2)`

=
`(1)/(10)`

Hence,
`(1)/(10)` is the probability of the coin landing on tail and a red marble being drawn.