Question

PLEASE HELP!

A school wants to put on a dance recital. Middle School dancers have short programs that run four minutes long. High School performers will dance longer with longer programs seven minutes in length. The entire program cannot have more than ten dances and the entire recital must be over in less than 90 minutes. What pair of inequalities BEST represents the number of short Middle School dances (M) and the number of longer High School dances (H) that can be performed given these limitations?

Answer 1

Answer: M + H ≤ 10 and 4 M + 7 H < 90

Explanation:

Here H represents the number of High school dance and M represents the number of middle school dance,

Also, the time take by High school dances = 7 minutes

While, the time taken by middle school dances = 4 minutes

Thus, the total time taken by high school dances = 7 H

And, the time taken by middle school dances = 4 M

According to the question,

The entire program cannot have more than ten dances

That is, M + H ≤ 10

And, the entire recital must be over in less than 90 minutes,

That is, 4 M + 7 H < 90

Answer 2

The pair of inequality are 4M +7H < 90 and M + H ≤ 10 ,

Explanation:

Consider, the number of short Middle School dances denoted by (M) and the number of longer High School dances denoted by (H)

We have to find the pair of inequalities BEST represents the number of short Middle School dances and the number of longer High School dances that can be performed in the given limitations.

1) Middle School dancers have short programs that run four minutes long and the high School performers will dance with longer programs seven minutes in length.

Also given the entire recital must be over in less than 90 minutes.

Mathematically represented as , 4M +7H < 90.

Also, given that the entire program cannot have more than ten dances.

That is total number of middle school dance and high school dance cannot exceed 10

Mathematically represented as , M + H ≤ 10.

Thus, the pair of inequality are 4M +7H < 90 and M + H ≤ 10.