Answer:
B
Explanation:
Since the triangle is right use the sine/ tangent ratios to solve for x and y
note sin60° =
and tan60° =
![√(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3jkdozb6pk3x1px4ym8d058os0wzvynm5a.png)
sin60° =
=
![(3√(6) )/(y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/fm0q6e75ny2q90ez50lzk1y2uy0m559v9t.png)
ysin60° = 3
![√(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ioc94yndeogljnfffe39yptishjhrbwo38.png)
y ×
= 3
![√(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ioc94yndeogljnfffe39yptishjhrbwo38.png)
multiply both sides by 2 and divide by
![√(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3jkdozb6pk3x1px4ym8d058os0wzvynm5a.png)
y v= 6
= 6
![√(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t462m14cxkj26cw9cmocfpgj44y1v8li5n.png)
tan60° =
=
![(3√(6) )/(x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zk7j5rvuog6vkh5ocxggt0azns9sgucn5f.png)
xtan60° = 3
![√(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ioc94yndeogljnfffe39yptishjhrbwo38.png)
x ×
= 3
![√(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ioc94yndeogljnfffe39yptishjhrbwo38.png)
divide both sides by
![√(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3jkdozb6pk3x1px4ym8d058os0wzvynm5a.png)
x = 3
= 3
![√(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t462m14cxkj26cw9cmocfpgj44y1v8li5n.png)