Question

Here's the work I've done. Is it right?

V=πr^2h
π(0.375)^2(0.80)
=0.4m^3 (smallest cylinder)
π(0.625)^2(0.80)
=1.0m^3 (middle cylinder)
0.70+0.80
=1.5m (height for big cylinder)
π(1.5)^2(1.5)
=10.6m^3
10.6m^3+0.4m^3+1.0m^3
=12.0m^3
The spa will fit 12.0m^3 of water

Answer 1

Answer:
`6.67m^3`

Explanation:

For hemisphere...

diameter (d1) = 3m

radius (r1) = (3/2)m

The total volume of the hemisphere

`v1=(2)/(3) \pi (r1)^3`

`=(2)/(3) \pi ((3)/(2) )^3`

`=(9)/(4) \pi`

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For smaller cylinder

diameter (d2) = 0.75

radius (r2) = 0.75/2m

height (h2) = 0.80m

Volume of smaller cylinder

(V2) =
`(1)/(3) \pi (r2)^2h2`

`=(1)/(3) \pi ((0.75)/(2) )^2*0.80`

`=(3)/(80) \pi`

------------------------------------------------------------------------

For bigger cylinder

Volume of bigger cylinder =

`V3=(1)/(3) \pi ((1.25)/(2) )^2*0.70`

`=(35)/(384) \pi`

-----------------------------------------------------------------------

Volume of water =
`(v1 - v2 - v3) =(9)/(4) \pi -(3)/(80) \pi -(35)/(384) \pi = 6.67 m^3`