Question

If f(x) = 2x^2 + 1 and g(x) = x2 – 7, find (f + g)(x).

4x^2+1/2x-1
4x^2+3/2x-1
6x^2-7
4x^2+3/2x-7

Answer 1

(f + g)(x) = 3x² - 6

Explanation:

(f + g)(x) = f(x) + g(x)

f(x) = 2x² + 1, g(x) = x² - 7.

Substitute:

(f + g)(x) = (2x² + 1) + (x² - 7) = (2x² + x²) + (1 - 7) = 3x² - 6