Question

How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium three nitrate and lead

Answer 1

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

Step-by-step explanation

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as
`\text{Pb}^(2+)` ions. The formula for a nitrate ion is
`{\text{NO}_3}^(-)`. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each
`\text{Pb}^(2+)` ion in lead nitrate would pair up with two
`{\text{NO}_3}^(-)` ions. The formula for lead nitrate will be
`\text{Pb}({\text{NO}_3})_2`. Each formula unit of lead nitrate will contain one
`\text{Pb}^(2+)` ion and two
`{\text{NO}_3}^(-)` ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as
`\text{Cr}^(3+)`. Similarly, each
`\text{Cr}^(3+)` will pair up with three
`{\text{NO}_3}^(-)` ions. The formula for chromium (III) nitrate will be
`\text{Cr}(\text{NO}_3})_3`. Each formula unit of chromium (III) nitrate will contain one
`{\text{NO}_3}^(-)` ion and three
`{\text{NO}_3}^(-)` ions.

0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of
`{\text{NO}_3}^(-)` ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.