Answer:
Option A. Y(15,0)
Explanation:
A=(1,0)=(xa,ya)→xa=1, ya=0
B=(5,0)=(xb,yb)→xb=5, yb=0
C=(2,3)=(xc,yc)→xc=2, yc=3
X=(7,0)=(xx,yx)→xx=7, yx=0
Z=(9,6)=(xz,yz)→xz=9, yz=6
We can see that the point C=(2,3) is transformed to point Z=(9,6)
There is a dilation from ABC to XYZ:
Factor of dilation: f=yz/yc=6/3→f=2
f*xc=2*2=4 different to xz=9, then, there is a translation too to the right:
xz-xc=9-4=5 units
Then, the transformation is a dilation with a factor of 2 and a horizontal translation to the right of 5 units, let's check it:
xz=f*xc+5=2*2+5=4+5→xz=9 ok
yz=f*yc=2*3→yz=6 ok
xx=f*xa+5=2*1+5=2+5→xx=7 ok
yx=f*ya=2*0→yx=0 ok
Then:
xy=f*xb+5=2*5+5=10+5→xy=15
yy=f*yb=2*0→yy=0
Y=(xy,yy)→Y=(15,0)