Question

A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of 21.0°C and a pressure of 122.2kPa. What was the original pressure on the container?

Answer 1

108 kPa

Step-by-step explanation:

To solve this problem, we can use the Combined Gas Laws:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁

p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?; V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the pressure

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)

= 122.2 kPa × 0.8542 × 1.0357

= 108 kPa